Example

Solving (3x8)(x1)=3x(3x - 8)(x - 1) = 3x

Solve (3x8)(x1)=3x(3x - 8)(x - 1) = 3x by first multiplying the binomials and then writing the quadratic equation in standard form.

Step 1 — Multiply the binomials: Expand the left side using FOIL: 3x211x+8=3x3x^2 - 11x + 8 = 3x

Step 2 — Write in standard form: Subtract 3x3x from both sides to set the equation to zero: 3x214x+8=03x^2 - 14x + 8 = 0

Step 3 — Factor the trinomial: (3x2)(x4)=0(3x - 2)(x - 4) = 0

Step 4 — Apply the Zero Product Property: Set each factor to zero: 3x2=0orx4=03x - 2 = 0 \quad \text{or} \quad x - 4 = 0

Step 5 — Solve each equation: 3x=2    x=23orx=43x = 2 \implies x = \frac{2}{3} \quad \text{or} \quad x = 4

Step 6 — Check: The check is left as an exercise. The solutions are x=23x = \frac{2}{3} and x=4x = 4.

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Updated 2026-04-30

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