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Determining Whether an Ordered Triple is a Solution: (4,1,5)(4, -1, -5)

To evaluate effectively whether the ordered triple (4,1,5)(4, -1, -5) stands as a valid solution applying to the system of equations \left\{\begin{array}{l} 3x + y + z = 2 \ x + 2y + z = -3 \ 3x + y + 2z = 4 \end{array} ight., perform a direct substitution of the isolated values x=4x = 4, y=1y = -1, and z=5z = -5 into the provided algebraic expressions. Focusing first on the initial equation, the substitution predictably yields 3(4)+(1)+(5)=1215=63(4) + (-1) + (-5) = 12 - 1 - 5 = 6. Because the evaluated quantity 66 blatantly differs closely from the required mathematical target of 22, the primary statement registers completely false. A true solution must universally satisfy every distinct formula included; thus, verifying the failure on the first equation guarantees absolutely that (4,1,5)(4, -1, -5) is not a functional solution for the system.

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Updated 2026-04-25

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