Example

Example: Solving and Graphing 53x15 - 3x \leq -1 or 8+2x58 + 2x \leq 5

To solve the compound inequality 53x15 - 3x \leq -1 or 8+2x58 + 2x \leq 5, solve each inequality individually. For the first inequality, subtracting 5 yields 3x6-3x \leq -6, and dividing by -3 (which reverses the inequality sign) gives x2x \geq 2. For the second inequality, subtracting 8 yields 2x32x \leq -3, and dividing by 2 gives x32x \leq -\frac{3}{2}. Graphing these solutions reveals that x2x \geq 2 is a region shaded to the right of a bracket at 2, while x32x \leq -\frac{3}{2} is a region shaded to the left of a bracket at 32-\frac{3}{2}. The solution to the 'or' compound inequality is the union of these two graphs, which consists of all numbers that satisfy either condition. In interval notation, this combined solution is written as (,32][2,)(-\infty, -\frac{3}{2}] \cup [2, \infty).

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Updated 2026-05-26

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