To practice solving another compound inequality connected by 'or', evaluate $2 - 5x \leq -3$ or $5 + 2x \leq 3$. For the first inequality, subtracting 2 yields $-5x \leq -5$, and dividing by -5 (reversing the inequality sign) gives $x \geq 1$. For the second inequality, subtracting 5 yields $2x \leq -2$, and dividing by 2 gives $x \leq -1$. Graphing both results demonstrates that the union consists of two distinct intervals: numbers less than or equal to -1 and numbers greater than or equal to 1. In interval notation, this combined solution is written as $(-\infty, -1] \cup [1, \infty)$.