Example

Factoring 18x23xy10y218x^2 - 3xy - 10y^2

To factor the two-variable trinomial 18x23xy10y218x^2 - 3xy - 10y^2 using trial and error, evaluate combinations of factors from the first and last terms. The factor pairs for the first term 18x218x^2 include x18xx \cdot 18x, 2x9x2x \cdot 9x, and 3x6x3x \cdot 6x. Because the last term 10y2-10y^2 is negative, its factors must have opposite signs, such as 2y2y and 5y-5y. Test different binomial combinations to find the arrangement where the sum of the inner and outer products equals the middle term, 3xy-3xy. Selecting the binomials (3x+2y)(3x + 2y) and (6x5y)(6x - 5y) results in an outer product of 15xy-15xy and an inner product of 12xy12xy. Adding these together gives 15xy+12xy=3xy-15xy + 12xy = -3xy, which matches the middle term. Thus, the completely factored form is (3x+2y)(6x5y)(3x + 2y)(6x - 5y).

0

1

Updated 2026-04-29

Contributors are:

Who are from:

Tags

OpenStax

Intermediate Algebra @ OpenStax

Ch.6 Factoring - Intermediate Algebra @ OpenStax

Algebra

Related