Example

Factoring 10y237y+710y^2 - 37y + 7

To factor the trinomial 10y237y+710y^2 - 37y + 7 completely using trial and error:

Step 1 — Verify the expression is in descending order. The trinomial 10y237y+710y^2 - 37y + 7 is arranged correctly.

Step 2 — Find the factors of the first term, 10y210y^2. The possible binomial first terms are y10yy \cdot 10y and 2y5y2y \cdot 5y.

Step 3 — Find the factors of the last term, 77. Since the last term is positive and the middle term is negative, both factors must be negative: 1-1 and 7-7.

Step 4 — Test combinations to match the middle term of 37y-37y.

  • For yy and 10y10y:
    • (y1)(10y7)(y - 1)(10y - 7) gives a middle term of 17y-17y.
    • (y7)(10y1)(y - 7)(10y - 1) gives a middle term of 71y-71y.
  • For 2y2y and 5y5y:
    • (2y1)(5y7)(2y - 1)(5y - 7) gives a middle term of 19y-19y.
    • (2y7)(5y1)(2y - 7)(5y - 1) gives a middle term of 37y-37y. ✓

The correct factors are (2y7)(5y1)(2y - 7)(5y - 1).

Step 5 — Check by multiplying: (2y7)(5y1)=10y22y35y+7=10y237y+7(2y - 7)(5y - 1) = 10y^2 - 2y - 35y + 7 = 10y^2 - 37y + 7.

The completely factored form is (2y7)(5y1)(2y - 7)(5y - 1).

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Updated 2026-04-29

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