Example

Finding the Equation of a Horizontal Line Through (2,6)(-2, -6) Using Point-Slope Form

To find the equation of a horizontal line containing the point (2,6)(-2, -6), substitute its given point and zero slope into the point-slope form.

Step 1 — Identify the slope: Every horizontal line has a slope of 00, so m=0m = 0.

Step 2 — Identify the point: The given point is (x1,y1)=(2,6)(x_1, y_1) = (-2, -6).

Step 3 — Substitute into the point-slope form yy1=m(xx1)y - y_1 = m(x - x_1): y(6)=0(x(2))y - (-6) = 0(x - (-2))

Step 4 — Simplify: Distributing zero eliminates the entire right side of the equation: y+6=0y + 6 = 0 y=6y = -6

Step 5 — Write in slope-intercept form: Although y=6y = -6 is already in the y=by = b format characteristic of a horizontal line, it could also be explicitly written as y=0x6y = 0x - 6.

0

1

Updated 2026-04-23

Contributors are:

Who are from:

Tags

OpenStax

Intermediate Algebra @ OpenStax

Ch.3 Graphs and Functions - Intermediate Algebra @ OpenStax

Algebra

Related