Example

Finding the Equation of a Line with Slope 25\frac{2}{5} Through (10,3)(10, 3)

To find the equation of a line with slope m=25m = \frac{2}{5} that passes through the point (10,3)(10, 3), apply the four-step procedure and write the result in slope-intercept form.

Step 1 — Identify the slope: m=25m = \frac{2}{5}.

Step 2 — Identify the point: (x1,y1)=(10,3)(x_1, y_1) = (10, 3).

Step 3 — Substitute into the point-slope form yy1=m(xx1)y - y_1 = m(x - x_1):

y3=25(x10)y - 3 = \frac{2}{5}(x - 10)

Distribute 25\frac{2}{5} on the right side:

y3=25x4y - 3 = \frac{2}{5}x - 4

Step 4 — Write in slope-intercept form by adding 3 to both sides:

y=25x1y = \frac{2}{5}x - 1

The equation of the line is y=25x1y = \frac{2}{5}x - 1.

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Updated 2026-04-21

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