Example

Finding the Equation of a Line with Slope 25-\frac{2}{5} Through (10,5)(10, -5)

To find the equation of a line with slope m=25m = -\frac{2}{5} that contains the point (10,5)(10, -5), apply the procedure to write the equation in slope-intercept form. First, identify the slope as m=25m = -\frac{2}{5} and the specific point as (x1,y1)=(10,5)(x_1, y_1) = (10, -5). Next, substitute these values into the point-slope form, yy1=m(xx1)y - y_1 = m(x - x_1), resulting in y(5)=25(x10)y - (-5) = -\frac{2}{5}(x - 10). Simplify this by recognizing that subtracting a negative is equivalent to addition, yielding y+5=25(x10)y + 5 = -\frac{2}{5}(x - 10). Distribute the slope on the right side to get y+5=25x+4y + 5 = -\frac{2}{5}x + 4. Finally, rewrite the equation in slope-intercept form by subtracting 55 from both sides to isolate yy, which gives the final equation: y=25x1y = -\frac{2}{5}x - 1.

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Updated 2026-05-03

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