Example

Finding the Equation of a Line with Slope 34-\frac{3}{4} Through (4,7)(4, -7)

To find the equation of a line with slope m=34m = -\frac{3}{4} that contains the point (4,7)(4, -7), apply the procedure to write the equation in slope-intercept form. Begin by identifying the given slope m=34m = -\frac{3}{4} and the point (x1,y1)=(4,7)(x_1, y_1) = (4, -7). Substitute these values into the point-slope form, yy1=m(xx1)y - y_1 = m(x - x_1), which yields y(7)=34(x4)y - (-7) = -\frac{3}{4}(x - 4). Simplifying the left side gives y+7=34(x4)y + 7 = -\frac{3}{4}(x - 4). Distribute the negative fractional slope on the right side to obtain y+7=34x+3y + 7 = -\frac{3}{4}x + 3. Lastly, express the equation in slope-intercept form by subtracting 77 from both sides, yielding the final equation: y=34x4y = -\frac{3}{4}x - 4.

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Updated 2026-05-03

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