Example

Factoring 1000m3125n31000m^3 - 125n^3

To factor the binomial 1000m3125n31000m^3 - 125n^3, note that both terms are perfect cubes: 1000m3=(10m)31000m^3 = (10m)^3 and 125n3=(5n)3125n^3 = (5n)^3. Applying the difference of cubes pattern, a3b3=(ab)(a2+ab+b2)a^3 - b^3 = (a - b)(a^2 + ab + b^2), yields (10m5n)((10m)2+(10m)(5n)+(5n)2)(10m - 5n)((10m)^2 + (10m)(5n) + (5n)^2). Simplifying this gives (10m5n)(100m2+50mn+25n2)(10m - 5n)(100m^2 + 50mn + 25n^2). Alternatively, factoring out the greatest common factor (GCF) of 125125 initially results in 125(8m3n3)125(8m^3 - n^3), which factors to the fully simplified form 125(2mn)(4m2+2mn+n2)125(2m - n)(4m^2 + 2mn + n^2).

0

1

Updated 2026-04-30

Contributors are:

Who are from:

Tags

OpenStax

Intermediate Algebra @ OpenStax

Ch.6 Factoring - Intermediate Algebra @ OpenStax

Algebra

Related