Example

Factoring (n+3)3125n3(n + 3)^3 - 125n^3

The expression (n+3)3125n3(n + 3)^3 - 125n^3 is a difference of cubes because the first term is already cubed and the second term is 125n3=(5n)3125n^3 = (5n)^3. Apply the difference of cubes pattern a3b3=(ab)(a2+ab+b2)a^3 - b^3 = (a - b)(a^2 + ab + b^2) by substituting a=n+3a = n + 3 and b=5nb = 5n. This gives ((n+3)5n)((n+3)2+(n+3)(5n)+(5n)2)((n + 3) - 5n)((n + 3)^2 + (n + 3)(5n) + (5n)^2). The first factor simplifies to (4n+3)(-4n + 3). The trinomial factor expands to (n2+6n+9)+(5n2+15n)+25n2(n^2 + 6n + 9) + (5n^2 + 15n) + 25n^2, which simplifies to 31n2+21n+931n^2 + 21n + 9. The final result is (4n+3)(31n2+21n+9)(-4n + 3)(31n^2 + 21n + 9).

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Updated 2026-04-30

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