Example

Factoring x3+64x^3 + 64

To factor the expression x3+64x^3 + 64, follow the procedure for factoring a sum of cubes.

Step 1: Verify the pattern. The expression is a sum, the first term x3x^3 is a perfect cube, and the last term 6464 is a perfect cube because 43=644^3 = 64. Step 2: Rewrite the terms as perfect cubes to identify the bases. Here, a=xa = x and b=4b = 4, so the expression is rewritten as x3+43x^3 + 4^3. Step 3: Apply the sum of cubes pattern, which is a3+b3=(a+b)(a2ab+b2)a^3 + b^3 = (a + b)(a^2 - ab + b^2). Substituting xx and 44 gives (x+4)(x2x4+42)(x + 4)(x^2 - x \cdot 4 + 4^2). Step 4: Simplify the terms within the trinomial to obtain the factored form: (x+4)(x24x+16)(x + 4)(x^2 - 4x + 16). Step 5: Check the result by multiplying the factors: (x+4)(x24x+16)=x34x2+16x+4x216x+64=x3+64(x + 4)(x^2 - 4x + 16) = x^3 - 4x^2 + 16x + 4x^2 - 16x + 64 = x^3 + 64. This confirms the factorization is correct.

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Updated 2026-04-30

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