Example

Factoring 8x327y38x^3 - 27y^3

To factor the binomial 8x327y38x^3 - 27y^3, observe that it is a difference of two cubes: 8x3=(2x)38x^3 = (2x)^3 and 27y3=(3y)327y^3 = (3y)^3. By applying the difference of cubes formula a3b3=(ab)(a2+ab+b2)a^3 - b^3 = (a - b)(a^2 + ab + b^2) with a=2xa = 2x and b=3yb = 3y, the expression becomes (2x3y)((2x)2+(2x)(3y)+(3y)2)(2x - 3y)((2x)^2 + (2x)(3y) + (3y)^2). Simplifying the trinomial factor gives the fully factored expression: (2x3y)(4x2+6xy+9y2)(2x - 3y)(4x^2 + 6xy + 9y^2).

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Updated 2026-04-30

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