Example

Finding the Intercepts of 3x+4y=23x + 4y = -2

To determine the intercepts of the equation 3x+4y=23x + 4y = -2, apply the algebraic substitution method for each axis crossing.

Finding the xx-intercept: Substitute y=0y = 0 and solve for xx: 3x+4(0)=23x + 4(0) = -2 3x=23x = -2 x=23x = -\frac{2}{3} The xx-intercept is the point (23,0)(-\frac{2}{3}, 0).

Finding the yy-intercept: Substitute x=0x = 0 and solve for yy: 3(0)+4y=23(0) + 4y = -2 4y=24y = -2 y=12y = -\frac{1}{2} The yy-intercept is the point (0,12)(0, -\frac{1}{2}).

The two intercepts of the line are (23,0)(-\frac{2}{3}, 0) and (0,12)(0, -\frac{1}{2}).

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Updated 2026-05-25

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