Example

Finding the Intercepts of x+4y=8x + 4y = 8

To calculate the intercepts for the linear equation x+4y=8x + 4y = 8, systematically set each coordinate to zero. Finding the x-intercept: Substitute y=0y = 0 and solve for xx: x+4(0)=8x + 4(0) = 8 x+0=8x + 0 = 8 x=8x = 8 The x-intercept is (8,0)(8, 0). Finding the y-intercept: Substitute x=0x = 0 and solve for yy: 0+4y=80 + 4y = 8 4y=84y = 8 y=2y = 2 The y-intercept is (0,2)(0, 2). Thus, the given equation's intercepts are the points (8,0)(8, 0) and (0,2)(0, 2).

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Updated 2026-05-03

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