Example

Finding the Intercepts of 2x+y=62x + y = 6

To determine the intercepts of the equation 2x+y=62x + y = 6, apply the substitution method for each axis crossing.

Finding the x-intercept: Set y=0y = 0 and solve for xx:

2x+0=62x + 0 = 6

2x=62x = 6

x=3x = 3

The x-intercept is the point (3,0)(3, 0).

Finding the y-intercept: Set x=0x = 0 and solve for yy:

2(0)+y=62(0) + y = 6

0+y=60 + y = 6

y=6y = 6

The y-intercept is the point (0,6)(0, 6).

The two intercepts of the line are (3,0)(3, 0) and (0,6)(0, 6).

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Updated 2026-04-21

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