Example

Finding the Intercepts of 3x+y=123x + y = 12

To find the intercepts of the linear equation 3x+y=123x + y = 12, substitute zero for each variable one at a time and solve for the other. Finding the x-intercept: Let y=0y = 0 and solve for xx: 3x+0=123x + 0 = 12 3x=123x = 12 x=4x = 4 The x-intercept is (4,0)(4, 0). Finding the y-intercept: Let x=0x = 0 and solve for yy: 3(0)+y=123(0) + y = 12 0+y=120 + y = 12 y=12y = 12 The y-intercept is (0,12)(0, 12). Therefore, the x-intercept is (4,0)(4, 0) and the y-intercept is (0,12)(0, 12).

0

1

Updated 2026-05-03

Contributors are:

Who are from:

Tags

OpenStax

Intermediate Algebra @ OpenStax

Ch.3 Graphs and Functions - Intermediate Algebra @ OpenStax

Algebra

Related