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Example

Solving (5n2)(6n1)=0(5n - 2)(6n - 1) = 0 Using the Zero Product Property

Solve (5n2)(6n1)=0(5n - 2)(6n - 1) = 0 by applying the Zero Product Property. This example involves multi-step linear equations whose solutions are fractions.

Step 1 — Set each factor equal to zero using the Zero Product Property:

5n2=0or6n1=05n - 2 = 0 \quad \text{or} \quad 6n - 1 = 0

Step 2 — Solve each linear equation. Unlike the simplest cases where a single operation isolates the variable, each equation here requires two steps (adding a constant and then dividing by the coefficient):

5n=2    n=25or6n=1    n=165n = 2 \implies n = \frac{2}{5} \quad \text{or} \quad 6n = 1 \implies n = \frac{1}{6}

Step 3 — Check both solutions by substituting each value into the original equation:

For n=25n = \frac{2}{5}: (5252)(6251)=(0)(75)=0\left(5 \cdot \frac{2}{5} - 2\right)\left(6 \cdot \frac{2}{5} - 1\right) = (0)\left(\frac{7}{5}\right) = 0

For n=16n = \frac{1}{6}: (5162)(6161)=(76)(0)=0\left(5 \cdot \frac{1}{6} - 2\right)\left(6 \cdot \frac{1}{6} - 1\right) = \left(-\frac{7}{6}\right)(0) = 0

The solutions are n=25n = \frac{2}{5} and n=16n = \frac{1}{6}. Each solution makes exactly one factor equal to zero while the other factor is nonzero, yet the product is zero in both cases.

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Updated 2026-04-21

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