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Solving 3p(10p+7)=03p(10p + 7) = 0 Using the Zero Product Property

Solve 3p(10p+7)=03p(10p + 7) = 0 by applying the Zero Product Property. In this equation, one of the two factors is a monomial (3p3p) rather than a binomial.

Step 1 — Set each factor equal to zero using the Zero Product Property:

3p=0or10p+7=03p = 0 \quad \text{or} \quad 10p + 7 = 0

Step 2 — Solve each equation. For the monomial factor, divide both sides by 33: p=0p = 0. For the binomial factor, subtract 77 and then divide by 1010:

10p=7    p=71010p = -7 \implies p = -\frac{7}{10}

Step 3 — Check both solutions by substituting each value into the original equation:

For p=0p = 0: 3(0)(10(0)+7)=07=03(0)(10(0) + 7) = 0 \cdot 7 = 0

For p=710p = -\frac{7}{10}: 3(710)(10(710)+7)=2110(0)=03\left(-\frac{7}{10}\right)\left(10\left(-\frac{7}{10}\right) + 7\right) = -\frac{21}{10}(0) = 0

The solutions are p=0p = 0 and p=710p = -\frac{7}{10}. When one factor is a monomial like 3p3p, setting it equal to zero immediately yields p=0p = 0 as a solution. This shows that zero itself can be a solution to a quadratic equation — the variable does not need to take on a nonzero value.

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Updated 2026-04-21

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