Example

Simplifying 100(0.04+0.35d)100(0.04 + 0.35d) Using the Distributive Property

To clear decimals in an algebraic expression like 100(0.04+0.35d)100(0.04 + 0.35d), distribute the constant multiplier to each term inside the parentheses. Multiplying 1000.04100 \cdot 0.04 simplifies to 44, and 1000.35d100 \cdot 0.35d gives 35d35d. The fully expanded and simplified expression is 4+35d4 + 35d, transforming a decimal problem into standard integer form.

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Updated 2026-04-21

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